Question 440270
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Hi
*[tex \LARGE\ \ log_2(5x-1) - log_2(x+7) = log_2(5x-1)/(x+7)=1 ]
*[tex \LARGE \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
  (5x-1)/(x+7) = 2^1
    5x-1 = 2(x+7)
       3x = 15
        x = 5
Familiarize Yourself with the Properties of Logarithms
*[tex \large\ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y)