<PRE><B>Question 440208</B>
They can be seated
(1) b g b g b g
or
(2) g b g b g b
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In (1), there are 3 boys that can be 1st
That leaves 2 boys that can be 2nd,
1 boy that can be 3rd
There are {{{ 3*2*1 = 6 }}} possibilities
The same is true for the girls, so there are
{{{ 6*6 = 36 }}} ways the boys and girls can be seated
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(2) follows the same rules, so the total number of
seating arrangements is {{{ 36 + 36 = 72 }}}
You probably should get a second opinion, too.
These things are tricky.

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