Question 440193
{{{X+3Y-12=0}}}.write it in {{{slope-intercept form

 and passing through point (-5, -9)

{{{3Y=-X+12}}}

{{{Y=-(1/3)X+4}}}


any two perpendicular lines are negative reciprocals of each other

if you're given the slope of{{{ -1/3}}}, you can find the perpendicular slope by this formula:

{{{mp=-1/m}}} is the perpendicular slope


{{{mp=-1/(-1/3)=3}}}........So the perpendicular slope is {{{mp=3}}}

Also since the unknown line goes through (-5,-9), we can find the equation by plugging in this info into the point-slope formula


Point-Slope Formula:


{{{y-y1=m(x-x1) }}}where m is the slope and (x1,y1) is the given point

{{{y-9=3(x-5) }}}

{{{y-9=3x-15 }}}

{{{y=3x-15+9 }}}
{{{y=3x-6 }}}

here is the graph:


{{{ graph( 500,500, -10, 10, -10, 10, -(1/3)x+4, 3x-6) }}}