Question 440168
3(x-5)^3/2-6=18
add 6 to both sides

3(x-5)^3/2=24
divide both sides by 3

(x-5)^3/2=8
square both sides

(x-5)^3=64
get the cube roots
x-5={{{64^(1/3))}}}
x-5=4
x=9
(x-5)^3-64 = 0
x^3-15 x^2+75 x-189 = 0
x = 3-2 i sqrt(3)
x = 3+2 i sqrt(3)
x=9