Question 440116
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Hi
The perimeter of a rectangle is 54 inches:  
2L + 2W = 54  OR L + W = 27  AND L = 27-W  
Let x AND (27-x) represent the width and length respectively
Question states***area is 176 square inches  Area(rectangle) = L*W
  (27-x)x = 176
     x^2 - 27x + 176 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (27 +- sqrt( 25 ))/(2) }}}
   x = 22/2 = 11, the width.  Length 16 
or x = 32/2 = 16, the width.  Length 11