Question 440037
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Hi
Let x, y, z represent the numbers:
The sum of three numbers is 4:  x + y + x = 4
The first, minus the second, plus 4 times the third, is 11: x - y +4z = 11
The third plus 3 times the first, plus the second, is -6: 3x + y + z = -6
Solving for x by substitution
x + y + z = 4  OR (y + z) = (4 - x)
x - y +4z = 11
3x + y + z = -6 AND 3x + (4-x) = -6   x = -5 
Solving for z by Eliminating y
x + y + z = 4  
x - y +4z = 11
 2x + 5z = 15
 2*-5 + 5z = 15
         z = 5  and y = 4  (x+y+z = -5 + 5 + z = 4)
the Numbers are -5,4,5