Question 439840
We solve this equation by factoring:{{{3x(x^2-9)-4(x^2-9)=(3x-4)(x-3)(x+3)=0}}}

To solve now the equation:{{{(3x-4)(x-3)(x+3)=0}}}we set to zero:

3x-4=0 => x=4/3; x-3=0 => x=3; x+3=0 => x=-3.

Answer:The roots of our equation are: {-3, 4/3, 3}.