Question 439763
    two cyclist start at the same time and travel toward the same direction. at the end of two hours, they are 50 meters APART . if the speed of the cyclist is twice of that the slower one , how fast did each travel?
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Applying the "distance formula" of d=rt
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Let x = speed of slower cyclist
then
2x = speed of faster cyclist
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2x+50 = 2(2x)
2x+50 = 4x
50 = 2x
25 meters/hour = x (slower cyclist)
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faster cyclist:
2x = 2(25) = 50 meters/hour