Question 439648
The domain and range of the function {{{y=2x^2+x-6}}} is the set of real numbers.

Since this function represent a parabola we rewrite it in standard form:

{{{y=2(x^2+(1/2)x+1/16)-1/8-6}}}, simplify {{{y=2(x+1/4)^2-49/8}}}.

The vertex is: (-1/4, -49/8). The minimum value is -49/8 and the axis of symmetry

is: x=-1/4. The x-intercepts are: (-2, 0)and (2/3, 0)

{{{graph(600, 600, -10, 10, -10, 10, 2x^2+x-6)}}}