Question 439695
first assign values to the base and the height of the triangle:
h=x
b=x+5
the formula of the area of a triangle is A=(1/2)b*h... so by substituting the values we get {{{52^2=(1/2)(x+5)*x}}} and simplifying this formula we get {{{x^2+5x=2(52^2)}}} which becomes {{{x^2+5x-5408=0}}} then *[invoke quadratic "x", 1, 5, -5408]
so to get the values of the length and base of the triangle we add 5 to 71.08 so the real values are height=71.08 and base=76.08