Question 439420
Let *[tex \theta] be the angle of elevation or depression of the road. Then *[tex \tan{\theta} = \frac{5 ft}{100 ft} = 1/20], and then we can solve for *[tex \theta].


When the angle is 2 degrees, then the percentage grade is equal to *[tex \tan{2^{ \circ}} \approx 0.0349 = 3.49%]