Question 439686
<font face="Times New Roman" size="+2">


The fundamental theorem of algebra says that a polynomial equation of degree n has exactly n roots, counting multiplicities.  A quadratic equation is a polynomial equation of degree 2, hence it ALWAYS has two roots.  You might have 2 real and unequal roots, a real root with a multiplicity of two, or a conjugate pair of complex roots of the form *[tex \Large a\ \pm\ bi] where *[tex \Large i] is the imaginary number defined by *[tex \Large i^2\ =\ -1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>