Question 45751
N(t) = -3t³ +23t² + 8t
(-t)(3t² +23t + 8) [Factor out the "-t" term]
(-t)(3t + 1)(t - 8)
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N(3)= (-t)(3t + 1)(t - 8)
[-(3)] [(3)(3) + 1][(3) - 8] [Substitute "3" for "t" and solve]
(-3)(9 + 1)(3 - 8) 
(-3)(10)(-5)
(-30)(-5)
150 [Final answer]
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