Question 439488
As you know the sum of exterior angels in each polygon is 360 degree.

Let n the number of angels in our polygon then the sum of interior angels is:

{{{(n-2)*180}}}, since this sum is twice the sum of exterior angels we write:

{{{(n-2)180=2*360}}} => {{{n-2=(2*360)/180}}} => {{{n-2=4}}} => {{{n=6}}}.

Answer:On the hexagon the sum of interior angels is twice of the sum of its exterior angels.