Question 439372
{{{dy/dx = ((3x-2)*4 - (4x + 1)*3)/(3x-2)^2 = (12x - 8 - 12x - 3)/(3x-2)^2 = 

-11/(3x-2)^2}}}
At (1, -2), {{{dy/dx = -11/(3*1 - 2)^2 = -11/1 = -11}}}, the slope of the tangent line.

==> Equation of the tangent line is y--2 = -11(x-1), or
y+2 = -11x + 11, or y = -11x + 9.