Question 439372
Can I get help with the following problem please!!
Find the equation of the tangent line to the curve y = (4x + 1) / (3x - 2) at the point (1, -2). (Write the line in y = mx + b form)

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f'(x) = [(3x-2)(4)-(4x+1)/(3)]/(3x-2)^2
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f' = [(12x-8)-(4x+1)]/(3x-2)^2
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f' = [8x-9]/[3x-2]^2
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f'(1,-2) = [8-9]/[3-2]^2 = 1/1 = 1
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Form: y = mx + b
-2 = 1*1 + b
b = -3
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Equation of the tangent line at (1,-2):
y = x-3
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Cheers,
Stan H.