Question 439197
 Could someone pleas show me step by step how to graph the system of inequalities?
x+y<6 (All are greater than or equal to and all less than are are 
less than or equal to) 
2x+y<6
x>0
y>0
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Note: You don't directly graph inequalities.  You first of all
graph the boundary of the inequality, which is always an equality.
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To graph x+y < 6
Graph y = -x+6 as a dashed line.
Shade the half-plane below the line.
{{{graph(400,300,-10,10,-10,10,y< -x+6)}}}

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To graph 2x+y< 6 
Graph y = -2x+6 as a dashed line
Shade the half-plane below the line
{{{graph(400,300,-10,10,-10,10,y <-2x+6)}}}

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The solution set is the intersection
of those two half-planes in the 1st Quadrant.
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You only look in the 1st Quadrant because you
have x> 0 and y> 0
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{{{graph(400,300,-10,10,-10,10,y< -x+6,y <-2x+6)}}}
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cheers,
Stan H.
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