Question 439180
Let x cm the perimeter of square 2, and x/4 the length of its side.
Perimeter of square 1 is (x+36) cm and its side (x+36)/4 cm.

The area of square 2 is:{{{(x/4)^2}}} and the area of square 1 {{{((x+36)/4)^2}}}

Since the areas of these two squares differ with {{{243cm^2}}} we write:

{{{((x+36)/4)^2-(x/4)^2=243}}}, solving the final equation we find x=36 cm.

The area of a larger square is:{{{((36+36)/4)^2=324cm^2}}}.