Question 438962
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi
Determine the time necessary for $1000 to double 
if it is invested at interest rate r=10% compounded continously.
  2000 = $1000e^(.10*t) Compounding continously
 ln (2000/1000) = .10t
   6.9315 yrs  = t