Question 438437
What is log base 2 of x = 3-log base 2 of 2x
..
log2(x)=3-log2(2x)
log2(x)+log2(2x)=3
log2(x*2x)=3
convert to exponential form:(base raised to log of number=number)
2^3=x*2x
8=2x^2
x^2=4
x=2
x=-2 (reject,x>0
ans:
x=2