Question 438347
{{{ log(3,8)*log(8,9) }}}
then, applying "change of base" we get:
{{{(log(8)/log(3)) * (log(9)/log(8)) }}}
notice the log(8) cancels leaving:
{{{log(9)/log(3)}}}
or simply:
{{{log(3,9)}}}
{{{log(3,3^2)}}}
{{{2}}}