Question 438126
The center of the hyperbola is (4, 1).  

Transverse axis is parallel to the x-axis.

Here a = 2, and c = (4--2)/2 = 6/2 = 3, and {{{b^2 = c^2 - a^2 = 9 - 4 = 5}}}

==> The equation is {{{(x-4)^2/4 - (y - 1)^2/5 = 1}}}.