<PRE><B>Question 438164</B>
 what is the vertex of y=5x^2+2x-4

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Since 5 is positive, the parabola opens up.
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minimum occurs when x = -b/(2a) = -2/(10) = -1/5
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f(-1/5) = -4.2
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Vertex: (-0.2, -4.2)
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{{{graph(400,300,-10,10,-10,10,5x^2+2x-4)}}}
Cheers,
Stan H.</PRE>