Question 438113
{{{f(x)=(1/4)(x)-1/8}}}...your original function;

means you have {{{x=-1/2}}}

{{{f(-1/2)=(1/4)(-1/2)-1/8}}}...multiply {{{(1/4)(-1/2)=-1/8}}}


{{{f(-1/2)=-1/8-1/8}}}


{{{f(-1/2)=-2/8}}}


{{{f(-1/2)=-cross(2)1/cross(8)4}}}


{{{f(-1/2)=-1/4}}}