Question 438060
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I suspect that you have misrepresented your problem and that you really mean:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{1}{2}x]


rather than


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{1}{2x}]


Be that as it may, you can use the same basic process either way.


Step 1:  Pick a value for *[tex \Large x].  It can be anything you like, but I recommend small integers -- it makes the arithmetic easier.


Step 2:  Do the indicated arithmetic to determine the value of *[tex \Large y]


Step 3:  Create an ordered pair *[tex \Large (x,y)] using the selected value from step 1 and the calculated value from step 2.


Step 4:  Plot the point.


Step 5:  Repeat steps 1 through 4 with a different value for *[tex \Large x].


If you actually meant the linear equation that I suggested above, then plotting two points is sufficient.  Just draw a line all the way across your graph paper through the two plotted points.  If the equation is what you actually represented, namely *[tex \Large y\ =\ \frac{1}{2x}], then you have some more work to do.  You will have to repeat step 5 several times and you will have to avoid selecting the value zero for *[tex \Large x] at any time.  Don't forget to pick some negative as well as positive values for *[tex \Large x] so that you get both branches of your hyperbola.  When you think you have plotted enough points, then draw smooth curves through the two sets of points.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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