Question 438023
I need to graph this circle. 
x^2+y^2+4x-8y-5=0
..
x^2+y^2+4x-8y-5=0
completing the square
(x^2+4x+4)+(y^2-8y+16)=0+4+16=20
Equation:
(x+2)^2+(y-4)^2=20

This is a circle with center at (-2/4) with a radius of sqrt(20)=4.47..
see graph below:
..
y=4+((20-(x+2)^2))^.5

{{{ graph( 300, 300, -10 , 10,-10, 10, 4+(20-(x+2)^2)^.5,  4-(20-(x+2)^2)^.5) }}}