Question 437998
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Use the formula for the tangent of the difference:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \tan(A\ -\ B)\ =\ \frac{\tan(A)\ -\ \tan(B)}{1\ +\ \tan(A)\tan(B)}]


Just plug in the given values:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \tan(\phi\ -\ \theta)\ =\ \frac{\frac{3}{4}\ -\ \frac{1}{2}}{1\ +\ \frac{3}{4}\,\cdot\,\frac{1}{2}}]


and do the arithmetic.





John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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