Question 437902
<pre><font face = "consolas" color = "indigo" size = 4><b>

To stretch horizontally by a factor of k, the rule is:

Replace x by x/k

So we replace x by x/2 in

        xｲ + yｲ - 2x - 3 = 0

(x/2)ｲ + yｲ - 2(x/2) - 3 = 0

       xｲ/4 + yｲ - x - 3 = 0

Cl;earing of fractions:

      xｲ + 4yｲ - 4x - 12 = 0

That's all you were supposed to do.  However if you
place the circle and the ellipse in standard form
you get:

(x - 1)ｲ + (y - 0)ｲ = 2ｲ

which is this graph:

{{{drawing(400,2400/11,-3,8,-3,3, graph(400,2400/11,-3,8,-3,3),

circle(1,0,2) )}}}

And the ellipse has the standard equation

(x - 2)ｲ   (y - 0)ｲ
覧覧覧覧 + 覧覧覧覧 = 1
   4ｲ         2ｲ

and its graph is:

{{{drawing(400,2400/11,-3,8,-3,3, graph(400,2400/11,-3,8,-3,3),
arc(2,0,8,-4) )}}}

Edwin</pre>