Question 437967
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Hi, Note use of ^ (uppercase 6)

(2r+1)(12r^2 +5r-3)=0   |completing the factoring
(2r+1)(4r +3)(3r -1) = 0
(2r+1) = 0
   r = -1/2
(4r +3)= 0
  r = -3/4
(3r -1)= 0
  r = 1/3