Question 437900
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Hi
contrator one(2x) is twice as likely to win as contractor 3 (x)
contractor two(3x) is three times as likely to win as contractor three(x)
what are the probabilities of winning for each 
P(contractor one) = 2/6 = 1/3
P(contractor two) = 3/6 = 1/2
P(contractor three) = 1/6

Note: 2/6 + 3/6 + 1/6 = 1