Question 437891
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Hi
*[tex \LARGE\ \ log_5(x+3) - log_5x = log_5(x+3)/x) = 2 ]
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
  5^2 = (x+3)/x
 25x = x+3
 24x = 3
   x = 1/8