Question 437852
Let x inches the side of square. If we increase the side by 12 it becomes: x+12
If we decrease the side by 4 it becomes: x-4 inches.

The area of square was:{{{x^2}}}. The area of rectangle will be:{{{(x+12)(x-4)}}}

Since the rectangle and square have the same area, we write the equation:

{{{x^2=(x+12)(x-4)}}}, solve this equation: {{{x^2=x^2+8x-48}}} => {{{8x=48}}} =>

{{{x=6}}}. 

Answer:The side of square is 6 inches while the dimensions of rectangle are:

The length: 6+12=18 inches and the width: 6-4=2 inches.