Question 437775

{{{y = log 2(x + 3)+1}}}
find critical points
when x = -3
y = log2(1)
this is saying
{{{2^y = 1}}}
the only value of y that makes this true is {{{y = 0}}}- anything to the zero power is{{{1}}}

when x = 0
y = log2(4)
this says 
{{{2^y = 4}}}
{{{y = 2}}} makes this true

{{{ graph( 500, 500, -10, 10, -10, 10, log(2, (x+ 3)+1))}}}