Question 437664
{{{(-32)^(3/5)^""=(root(5,-32))^3=(-2)^3=-8}}}



So {{{(-32)^(3/5)^""=-8}}}



Things to note: 



1) {{{x^(m/n)^""=(root(n,x))^m}}}. So {{{(-32)^(3/5)^""=(root(5,-32))^3}}}



2) Since {{{(-2)^5=-32}}}, this means that {{{root(5,-32)=-2}}}