<PRE><B>Question 437604</B>
The parametric equations for a curve in the x-y plane are x=2+t^2 and y=4-3t. Determine the points where the curve intersects the x-axis. 
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When the curve hits the x-axis y = 0.
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Solve: 4-3t = 0
t = (4/3)
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Then x = 2+t^2
x = 2+(4/3)^2
x = 18/9 + 16/9
x = 34/9
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The curve intersects at (34/9,0)
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Cheers,
Stan H.</PRE>