<PRE><B>Question 437571</B>
Dawn, Serigo, Katrina, Sarah, Ian, Maria, and Kim have all been invited to a dinner party. They arrive randomly and each person arrives at a different time.
a) In how many ways can they arrive?:: 7! 
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b) In how many ways can Dawn arrive first and Kim last?::1*5!*1 = 5!
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c)Find the probability that Dawn will arrive first and Kim last.
Ans 5!/7! = 1/(7*6) = 1/42
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cheers,
Stan H.
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