Question 437518
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Presuming your ambiguously rendered equation is actually:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{t\ -\ 2}{t}\ =\ \frac{2}{t\ +\ 3}]


Cross multiply:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (t\ -\ 2)(t\ +\ 3)\ =\ 2t]


Now all you have to do is FOIL the two binomials in the LHS, collect terms to put the equation into standard quadratic form, and solve the resulting quadratic by your choice of method.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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