Question 437479
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Yes, you want a permutation.  That is because a red Model Z100 Barfmobile is different than a red MyDaddysFamilySedan.  So:


The number of permutations of 14 things taken 6 at a time is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{14!}{(14\ -\ 6)!}\ =\ 14\,\cdot\,13\,\cdot\,12\,\cdot\,11\,\cdot\,10\,\cdot\,9]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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