Question 45489
You have:
{{{3x^2-2x +1 = 0}}}
The best way to solve this is by usibng the qudratic solver {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
where
a = the amount of {{{x^2}}} = 3
b = the amount of x = -2
c = the number on the end =
The Right hand side of the equals ign MUST be zero!!!
Now plug in the values for a, b and c:
{{{x = (2 +- sqrt( 4-4*3*1 ))/(2*3) }}} 
{{{x = (2 +- sqrt( 4-12 ))/6 }}}
{{{x = (2 +- sqrt( -8 ))/6 }}}
{{{x = (2 +- 2*sqrt( -2 ))/6 }}}
{{{x = (2 +- 2i*sqrt( 2 ))/6 }}}
{{{x = 1/3 +- sqrt( 2 )/3*i }}}
where "i" represents the imaginary number {{{sqrt(-1)}}}


I hope this helps.
Adam
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