Question 437331
You can't solve, it's not an equation, you can simplify it:

{{{1/x}}} + {{{x/((2x+4))}}} - {{{2/((x^2+2x))}}} 
Factor the denominators
{{{1/x}}} + {{{x/(2(x+2))}}} - {{{2/(x(x+2))}}} 
The common denominator is 2x(x+2), so you got that right.
:
Now you have:
{{{(2(x+2) + (x*x) - (2*2))/(2x(x+2))}}}
:
{{{(2x + 4 + x^2 - 4)/(2x(x+2))}}}
:
{{{(x^2 + 2x)/(2x(x+2))}}} = {{{(x(x + 2))/(2x(x+2))}}}
Cancel (x+2), then cancel x
{{{(x)/(2x)}}} = {{{1/2}}}