Question 437355
To solve the equation:{{{x^(3/2)-3*x^(1/2)=0}}}, add on both sides {{{3x^(1/2)}}}

and after square both sides the result will be:{{{(x^(3/2))^2=(3x^(1/2))^2}}}=>

=> {{{x^3=9x}}} => {{{x^3-9x=0}}} => {{{x(x^2-9)=0}}}, solving the last equation 

we find the roots:

x=0 and (x-3)(x+3)=0 => x=-3 and x=3.

Answer: the solution of equation is the set: {-3, 0, 3}.