Question 437335
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Hi
(2, 1500)    |Using the point-slope formula, {{{m =(y[2] - y[1])/(x[2] - x[1])}}}
(10, 300 )  m = 1200/-8 = -150 (depreciating $150 per year)
Using the standard slope-intercept form for an equation of a line y = mx + b 
 where m = -150 is the slope and b the y-intercept.  
  V(t) = -150t + $1800   ($1500+$300 = $1800 brand new: t = 0)
Use the model to find the equipment model after 5 years.
  V(5) = -150*5 + $1800 = $1050
Use the model to determine when the equipment will have a value of $100.
  100 = -150t + 1800
     t = 1700/150 = 11 1/3 years