<PRE><B>Question 437322</B>
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This is just a proportion.  Cross-multiply and solve.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3x\ -\ 2}{2}\ =\ \frac{y}{8x^2\ -\ 2x\ -\ 1}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2y\ =\ \left(3x\ -\ 2\right)\left(8x^2\ -\ 2x\ -\ 1\right)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{\left(3x\ -\ 2\right)\left(8x^2\ -\ 2x\ -\ 1\right)}{2}]


All that is left is to simplify.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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