Question 437318
4x^3+4x^2-29x+21=(x-1)*(2x+7)*(2x-3)
so we get 
(x-1)*(2 x+7)
or
2x^2+5x-7
here are the steps
 2x-3 into 4x^3+4x^2-29x+21
first quotient is 2x^2
then 5x
4x^2-15x

then -7
-14x+21
with zero remainder