Question 437257
{{{graph(300, 300, -5, 5, -5, 5, -x^2-2x+3)}}}

This graph represent a parabola: {{{y=-x^2-2x+3=-(x^2+2x+1)+1+3=-(x+1)^2+4}}}

From the final expression we see that the vertex is: (-1, 4)

To find the y-intercept we make x=0: y=-0^2-2*0+3=3; (0, 3)

Other extra points are the x-intercepts: -x^2-2x+3=(x+3)(x-1)=0: x=-3 and x=1;

x-intercepts are:(-3, 0) and (1, 0).

Done.