Question 437258
The graph of this function is a parabola, which opens up because a=1>0.
From its graph we see that the curve intersect the x-axis at (-10, 0) and (-2, 0).

Check: {{{x^2+12x+20=(x+10)(x+2)=0}}}, for x=-10 and x=-2.

{{{graph(600, 600, -15, 5, -20, 25, x^2+12x+20)}}}