Question 436849
The acoustical intensity, I, of a sound wave is proportional to the square of
 the pressure amplitude, P, and inversely proportional to the velocity, v, of the wave.
 If I=0.6W/m^2 for P=30.0Pa and v=150m/s, find v if P=50 Pa and I=2.4W/m^2.
:
From the given information we can write a formula:
I = {{{(k*p^2)/v}}}, where k is the constant of variation
:
Using the given values, find k:
"If I=0.6W/m^2 for P=30.0Pa and v=150m/s
: 
.6 = {{{(k*30^2)/150}}}
150*.6 = 900k
90 = 900k
k = {{{90/900}}}
k = .1 the constant of variation
:
We can write the formula
I = {{{(.1p^2)/v}}}
:
"find v if P=50 Pa and I=2.4W/m^2."
2.4 = {{{(.1*50^2)/v}}} 
2.4v = .1*2500
v = {{{250/2.4}}}
v = 104.167 m/sec