Question 437124
6x^2-4x-3

vertex = x=-b/2a
vertex y= c-b^2/4a

x= -(-4)/2*6= 0.33
y= -3-(16/24)= -3.6666

Vertex ( 0.33,-3.6666)

xintercepts 
y=0
6x^2-4x-3=0

	Find the roots of the equation by quadratic formula						
							
a=	6	b=	-4	c=	-3		
							
b^2-4ac=16-72				
b^2-4ac=88   , {{{sqrt(	88)}}}=	9.38
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(4+9.38)/12		
x1=1.12					
x2=(4-9.38)/12			
x2= -0.45						
(-0.45,0) (1.12,0) x intercepts
......
y intercepts plug x=0
6x^2-4x-3
-3 is the y intercept