Question 436946
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Hi
line passing through the y-axis at 5 and perpendicular to the graph of 2x=3y+4
Using the standard slope-intercept form for an equation of a line y = mx + b
  where m is the slope and b the y-intercept. 
 2x = 3y+4  OR y = (-2/3)x - 4/3  Slope m = (-2/3)
New Line: 
 y = (3/2)x + 5   |Slopes of perpendicular lines are negative reciprocals