Question 436892


The problem is A=2, B=8, C=-80

{{{2x^2 + 8x -80=0}}}.....use quadratic formula

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} .....plug in A=2, B=8, C=-80

{{{x = (-8 +- sqrt( 8^2-4*2*(-80) ))/(2*2) }}}

{{{x = (-8 +- sqrt( 64+640 ))/4}}}

{{{x = (-8 +- sqrt( 704))/4}}}

{{{x = (-8 +- 26.53)/4}}}

roots:

{{{x = (-8 +26.53)/4}}}

{{{x = 18.53/4}}}

{{{x = 4.6325}}}

or

{{{x = (-8 -26.53)/4}}}

{{{x = (-34.53)/4}}}

{{{x = -8.6325}}}